Monday, 14 September 2015

VERIFIED WAEC GCE 2015/16 BIOLOGY PRACTICAL ANSWERS


waec-logo.png               BIOLOGY PRACTICAL ANSWERS

(1ai)
I-flower
II-hypocotyl
III-stem
IV-margin
V-midrib
VI-node/leaf stalk
VII-inflorescense
VIII-leaf

(1aii)
I-it carries out reproduction
II-it provides a space for the growth of flower
V-holds other part of the leaf together
VIII-aids the absorption of sunlight ie the
photosynthesis

(1bi)
A-Monocotyledon
B-Dicotyledon

(1bii)
A
-it has one seed leaf
-it has a parallel vein

B
-leaf has net vein
-it has two seeded leaf
1c)
A-rice,oil palm
B-groundnut,cowpea,mango
1di)
-A has parallel vein while B has net vein
-A has one seed leaf while B has two seed
leaves
-A has vibrous root while B has tap root
-A has the female and male parts of the
flower
at
different part while B has both the male and
female
parts at the same part of the flower
-A is a grass with long and narrow leaves
while B is a
legume with broad leaves

1dii)
-They are both flowering plants
-They are both seed plants
-They are both vascular plants

2a)
Food web

2b)
Producer(grass)
->primary consumer(cane
rat,grasshopper,mouse)
->secondary consumer(fox,lizard,snake)
->tertiary consumer(man,hawk,Eagle

2c)
I-The population of the lizards will increase
II-More energy would be passed into the chain
in
the web containing grasshopper,lizards,hawk
and
man
III-Less energy might be available to mouse
I-The population of lizards would decrease
II-Less energy would be passed into the chain
containing lizards
III-more energy would be available to mouse
and
cane rat

2d)
-Grass->mouse->snake->eagle->man
-Grass ->mouse ->Hawk->man
-Grass->mouse->snake ->eagle

VERIFIED WAEC GCE 2015/16 GEOGRAPHY AMSWERS (ESSAY & OBJ)

                GEOGRAPHY OBJ:

1-10: ABBCAAABDD
11-20: ABACBBDDCA
21-30: AAACABBCAA
31-40: CBADAACCDD
41-50: CDBADCBDAB

                   GEOGRAPHY THEORY

1a)
(i)
colonial ties: nigeria and britain share
international trade with one another
because britain colonised Nigeria and

(ii)Differences in natural resources:
nigeria and britain have differences in
raw materials. the nigerian cocoa, rubber
and crude is needed by britain.

(iii)the need to earn foreign exchange by
nigeria.

(iv)high level of technology.

(1b)
(i)cocoa
(ii)rubber
(iii)crude

(1c)
(i)political instability
(ii)inadequate production of goods
(iii)inadequatencapital
(iv)low value of currency
(v)government policies

2a)
(i)The pull factor is a factor that draws people
to a
new location.

(ii)The push factor involves a force which acts
to
drive people away from a place.

(2b)
-accessibility of the location by roads
-good climate
-availability of social amenities
-absence of disaster

(2c)
-environmental pollution: more wastes are
produced due to high concentration of people
and
these tend to cause pollution

-increase in crime rate: Robbery will be on the
in
tease partly due to unemployment

-high cost of living: it leads to high cost of
living as
only few facilities and goods are available to
the
people.
-housing congestion: high population leads to
poor
accommodation as the number of houses are
not
always for the people.

3a)
(i)inadequate and poor technology: most
of the
african countries are technologically
poor and
this explains why they invest in primary
industries

(ii)inadequate capital:most of the african
countries do not have enough fund to
setup
secondary industries, hence they
concentrate
on primary industries

(iii)inadequate infrastructure: most
african
countries do not have regular supply of
electricity and goodroads for secondary
industries and they concentrate on
primary
industry

(3b)
(i)poor infrasture: most african countries
do not
have good road and regular supply of
electricity to setup industries (ii)problem
of market: the demand for foods in
african countries is very low and this is
another
problem

(iii)problem of capital: it is very difficult
to get
loan from bank due to collateral problem

(iv)inadequate raw materials: raw
materials for indutries are not available
and this is another
problem

(3c)
(i)availability of loan: there should be
loan to
private people

(ii)the infrastructure amenities should be
developed i.e there should be regular
supply of
electricity and provision of good roads

(iii)there should be production of good
products for people to buy

(2c)
POVERTY:- Intensive urban growth can
lead to greater poverty, with local
governments unable to provide services
for all people.

ENVIRONMENTAL HAZARDS:- Urban
development can magnify the risk of
environmental hazards such as flash
flooding, hurricanes e.t.c
.
UNEMPLOYMENT:- Dues to the large and
teeming population provision of
employment opportunites will be limited.
Leading to unemployment of a large
number of people

AIR POLLUTION:- Concentrated energy use
leads to greater air pollution, also fumes
from smokes and exhaust pipes of
vehicles cause air pollution which has
adverse effect on human health.

(4a)
Draw the diagram

(4b)
i. Favourable climate

ii. Availability of fertile soil

iii. Availability of market

iv. Employment opportunities

(4c)
i. Increase in crime rate

ii. Insufficient food

(6a)
DRAW THE MAP

(6b)
-Low rainfall

-Problem of pest and diseases

-Problem of high temperature

-Poor soil

================================

(6c)
-Employment;cash crops creates job
for people

-Foreign exchange;It brings about
foreign exchange to the economy
through exportation

VERIFIED WAEC GCE 2015/16 GENERAL MATHEMATICS ANSWERS (ESSAY & OBJ)

                       MATHS OBJ

1-10 CBADBDDBDA
11-20 DCDBACDCCC
21-30 CACBCDCBCA
31-40 ADBABACDB
41-50 DbBBDBCAAD

^=means raise to power

/ means divide

* means times

1a. 1/2log 25/4- 2log10 4/5 log10 320/125
Log(25/4)^1/2-log(4/5)^2 log10 320/125
Log10 sqrt25/4-log16/25 log10 320/125
Log10 5/2-log10 16/25 log10 320/125
Log10 5/2 log10 320/125-log10 16/25
Log10 [5/2*320/125÷16/25]
Log10 [5/2*320/125*25/16]
Log10 10=1

1b.
% income= 20%
Grant per land =GHC€15.00
Total population from 2003-2007
=1.2*1.2*1.2*1.2*3000=6220.8
Total grant=population*grant per head =
6220.8*15
=ghc€93312
Total grant=GHC€93312

===========================

2a.
1/x 1/x 3=1/2
L.C.M=x(x 3)
X 3 x/x(x 3)=1/2
2(2x 3)/x(x 3)=1/2
2(2x 3)=x(x 3)
4x 6=x^2 3x
X^2 3x=4x 6
X^2 3x-4x-6=0
X^2-x-6=0
(X^2-3x) (2x-6)=0
X(x-3) 2(x-3)=0
(X 2)(x-3)=0
X=-2 or x=3

2b.
Let d bag of rice be X
Let d bag of beans be Y
X Y=17—>(I)
2250x 2400y=39600—>(2)
From eqtn (I)
X=17-y
Using elimination method to eliminate Y
2250x 2250y=38250—>(3)
2250x 2400y=39600—>(4)
Eqtn 4- eqtn 3
2400x-2250x = 39600-38250
150x=1350
X=1350/150
X=9
D trader bought 9bags of beans
4a. Draw a triangle
3^2 y^2=5^2
9 y^2=25
Y^2=25-9
Y^2=16
Y= sqrt16
Y=4
:. CosX tanX/sinX
4/3 3/4÷3/5
16 15/20 ÷3/5
31/20÷3/5
=31/20*5/3
=31/12
=2 7/12

4b.
From the diagram
200deg 32deg Ydeg=360deg(< at a point) Ydeg 232deg=360deg Ydeg=360deg-232deg Ydeg=128deg Ndeg=128deg(alternate < Xdeg=128deg 180deg Xdeg=308deg

================================

5a)
1. | 2. | 3. | 4. | 5. | 6. |

------------------------------------------
1|1,1|1,2 |1,3 |1,4 |1,5 |1,6 |
-------------------------------------------
2|2,1|2,2 |2,3 |2,4 |2,5|2,6 |
--------------------------------------------
3|3,1|3,2 |3,3 |3,4 |3,5|3,6 |
---------------------------------------------
4|4,1|4,2 |4,3 |4,4 |4,5|4,6 |
---------------------------------------------
5|5,1|5,2 |5,3 |5,4 |5,5|5,6 |
-----------------------------------------------
6|6,1|6,2 |6,3 |6,4 |6,5|6,6 |
------------------------------------------------

B) pr(sum of outcome is8) = 4/36 = 1/9 Bii) pr(product of outcom <10) = 30/36 = 5/6 Biii) pr(outcom contain atleast a 3) = 24/36 = 4/6 = 2/3

6a) = 2x (37x) = 75x = 2x X 37x = 75x [Note the small x are Base while big X is multiply] = (2xX) 3Xx 7Xx = 7Xx 5Xx = 2(3x 7) = 7x 5 = 6x 14 = 7x 5 = 6x - 7x = 5 - 14 = - x = - 9 = x = 9

6b) Let the no of boys = x No of girls = 5 x X 5 / X 2 = 5/4 Cross multiply 4(x 5) = 5(x 2) 4x 20 = 5x 10 4x - 5x = 10 - 20 X =10

6bi) Num of girls in class = x 5 = 10 5 = 15

6bii) total num of student = x x 5 = 10 10 5 = 25
6biii) probability of selectin a boy as class

prefect = 10/25. = 2/5

7a )
L a / n – 1 = d ———— (I)
2s = n (a 1) —————- (2)
From eq (1)
L a = d (n – 1) ————– (3)
Put eq (3 into 2)
2s = nd (n-1)
2s = d (n^2 – n)
S = d ( n^2 – n ) / 2 or
S = dn(n-1)/2

8a)
By using pythagoras
r^2 = (r - 8)^2 32^2
r^2 = r^2 - 16r 64 1024
16r = 64 1024
r = 1088/16
r = 68
r=68cm

8bi)
{st/pt/
q2=27^2 12^2
q=sqrt27^2 12^2
q=sqrt729 144
q=sqrt873
q=29.5cm

==================================

7a)
|PQ|^2 = |PB|^2 |BQ|^2
|PQ|^2 = (5 - x )^2 X^2
|PQ|^2 = 25 - 10x x^2 x^2 [note ^ means Raise
to power]
|PQ|^2 = 2x^2 - 10x 25
NB: PQ = QR (side of a square)
Area of PQRS = PQ x QR
= PQ x PQ = PQ^2
Area of PQRS = (2x^2 - 10x 25)m square
GIVEN: 2x^2 - 10 25 = 3/5 of 25
= 2x^2 - 10x 10 = 0
= x^2 - 5 5 = 0
Using General Formular mthod
X = -(-5) ± Square Root (-5)^2 - 4(1)(5)/ (2 x 1)
X = 5 ± Square Root 25 - 20/ 2
X = 5 ± Square Root 5 / 2
X = 5 Square Root 5 / 2 OR 5 - Square Root 5 / 2
X = 3.62 or 1.68

7b )
L a / n - 1 = d ------------ (I)
2s = n (a 1) ---------------- (2)
From eq (1)
L a = d (n - 1) -------------- (3)
Put eq (3 into 2)
2s = nd (n-1)
2s = d (n^2 - n)
S = d ( n^2 - n ) / 2 or
S = dn(n-1)/2
==================================

VERIFIED WAEC GCE 2015/16 BIOLOGY ANSWERS (ESSAY & OBJ)

                      Biology obj
1DBBBCDBBAB
11 CCBDBBBCCD
21 DCDCC – CCC-
31 BACABCCCAB
41 BBAACAB – CC

1a )
Blood – tissue,
guinea pig – organism ,
hebiscus flower- organ.
Human skeleton – system .
Plasmodium – cell .

1b )
Homeostasis can be defined as a property
of an organism or
system that helps it maintain its
parameters within a normal range
of values . It is key to life , and failures in
homeostasis can lead to
diseases like hypertension and diabetes .

1c )
When d body fluids become acidic ie d
concentration of acids
becomes higher than that of d bases d
kidney excretes more acid .

– When d concentration of d base is
higher the kidney will excrete
more salt with urine.

1d )
– Inflamation of d nephron caused by
bacteria . It causes glomeruli
to filter d blood completely leading to
useful substances like
protein to pass out with d urine excreted
by d kidney
.
– Secondly wen amino acids and calcium
phosphate settle in d
kidney they form kidney stone which
obstructs the free flow of
urine

2a )
Photosynthesis can be represented using a
chemical equation .
The overall balanced equation is . . .
6CO 2 + 6 H 2 O – – – – – – > C 6 H 12 O
6 + 6O 2
Sunlight energy
Where: CO 2 = carbon dioxide
H 2 O = water
Light energy is required
C 6 H 12 O 6 = glucose
O 2 = oxygen

2b ) Diagram of Dicotyledon leaf and
fully labeled

2c )
i)To produce substances that break down
fats ,
convert glucose to glycogen ,

ii) produce urea ( the main substance of
urine ), make certain amino
acids (the building blocks of proteins ) ,
filter harmful substances
from the blood (such as alcohol ),

iii )Storage of vitamins and minerals
( vitamins A , D , K and B 12 )
and maintain a proper level or glucose in
the blood .

Iv )The liver is also responsible fore
producing cholesterol.

v ) It produces about 80 % of the
cholesterol in your body
.
6ai )
(i) By Mechanism

(ii ) By species

6aii )
(i) Food

(ii ) Water

(iii ) Territory

(iv ) IDK

(6 C )
(i) Fluid Feeder :
are organisms that feed on the fluid of
other organisms. It can
refer to Hematophagy , feeding on blood ,
which include bedbug ,
butterflies , hood mockingbird , oxpeckers
and anopheles stephensi
mosquito Nectarivore, feeding on nectar
include bats visit open
flowers where the nectar is not deeply
hidden, hawkmoths and
hummingbird Plant sap feeders

(ii )Filter Feeder : are a sub group of
suspension feeding animals
that feed by straining suspended matter
and food particles from
water, typically by passing the water
over a specialized filtering
structure . Some animals that use this
method of feeding are
clams , krill , sponges , baleen , whales,
and fish (including sharks )

6D.
(i) to move the position of th hairs

(ii ) adjust the angle of hair shafts to
change the degree of
cornfield layer idk

(iii )
(i) maintaing the epidermal permeability
barrier , structure and
differentiation

(ii ) skin specific hormonal signalling
oo == GOODLUCK == oo

VERIFIED WAEC GCE 2015/16 PHYSICS AANSWERS

(1a)
Tabulate.
Under s/n: 1,2,3,4,5
Under M(N): 140,120,110,84,66
Under tita(o): 24,32,38,51,62
Under Sin tita: 0.4067, 0.5299,0.6156,
0.7771,0.8829.
Note that 1cm =20N
(1aviii)

– I would ensure that the meter rules
balanced before the readings.

– I would avoid error due to parallax

(1bi)
i. Total forces in one direction are
equal to the forces in opposite
direction.

ii. The algebraic sum of the moment
of all forces about any point should
be zero.

(1bii.)
The moment of force at equilibrium
point o is equal to,
sum of clockwise moment = sum of
anti- clockwise moment
OC*M=CD*W.

====================================

(3a)
(i)d1=1.40cm, d2=1.55cm,

d3=1.75cm, d4=2.1cm, d5=2.3cm

Real values of di
d1=1.4*0.5=0.7mm
d2=1.55*0.5=0.77mm
d3=1.75*0.5=0.875mm
d4=2.1*0.5=1.05mm
d5=2.3*0.5=1.15mm

(ii)Ia1=2.4A, Ia2=3.8A, Ia3=5.0A,
Ia4=7.4A, Ia5=11.6A
Ib1=2.4A, Ib2=3.6A, Ib3=5.2A,
Ib4=7.5A, Ib5=11.6A

(iii)I=(Ia+Ib)/2
I1=(2.4+2.4)/2=2.4A
I2=(3.8+3.6)/2=3.7A
I3=(5.0+5.2)/2=5.1A
I4=(7.4+7.5)/2=7.45A
I5=(11.6+11.6)/2=11.6A

(3aiv)
logd1=log0.7=-0.15mm
logd2=log0.775=0.11mm
logd3=log0.875=0.06mm
logd4=log1.05=0.02mm
logd5=log1.15=0.06mm
logI1=log2.4=0.38
logI2=log3.7=0.57
logI3=log5.1=0.71
logI4=log7.45=0.87
logI5=log11.6=1.06

(3av)
TABULATE
S/N; 1,2,,3,4,5
di(cm);1.40,1.55,1.75,2.10,2.30
di(mm);0.70,0.78,0.88,1.05,1.15
Ia(A);2.4,3.8,5.0,7.4,11.6
Ib(A);2.4,3.6,5.2,7.5,11.6
I(A);2.4,3.7,5.1,7.5,11.6
logd!(mm);-0.15,-0.11,-0.06,0.02,0.06
logI1;0.38,0.57,0.71,0.87,1.06

(3avi)
|Slope(s)=change in logI/change in
logd
=(0.87-0.57)/(0.02-(-0.11))
=0.3/0.13=2.3A

(3avii)
-I will ensure the circuit is open
when no readings are not taken

-i will ensure tight connection

(3bi)
diameter(d)=1.09mm

(ii)
R=eL/A
R=(5.0*10^-2*0.01)/(pie/4)*(0.001)^2
R=(5*10^-4)/(0.7855*1*10^-6)
=6.37*10^2ohm
P=I^2R
=10^2*6.37*10^2
=6.37*10^4W

Wednesday, 26 August 2015

WAEC GCE 2015 OFFICIAL TIMETABLE


WAEC GCE 2015 TIMETABLE BY NOBLELODGE.BLOGSPOT.COM

+++++++++++++++++++++++++++++

Runs In Progress......



2015-WAEC-GCE-TIME-TABLE SATURDAY 5TH SEPT 2015 Economics 2 (Essay) 8.30 am-10.30am Economics 1 (Objective) 10.30 am - 11.30am

=============================

TUESDAY 8TH SEPT 2015 Financial Account 2(Essay) 8.30 am -11.00 am Financial Account 1 (Obj) 11.00 am -12.00 pm

=============================

WEDNESDAY 9TH SEPT 2015 HAUSA/IGBO/YORUBA(ESSAY) 9.30am-11.30am HAUSA/IGBO/YORUBA(OBJ) 11.30am-12.30am

=============================

THURSDAY 10TH SEPT 2015 Physics 3 (Alternative to Practical Work) 8.30 am - 11.15 am

=============================

FRIDAY 11TH SEPT 2015 Biology 2 (Essay) 8.30 am - 10.10 am Biology 1 (Obj) 10.10 am - 11.00 am

=============================

SATURDAY 12TH SEPT 2015 General Mathematics(Essay) 8.30 am - 11.00 am General Mathematics(Obj) 1.00pm-2.30pm

=============================

MONDAY 14TH SEPT 2015 Geography2 (Essay) 8.30am-10.30am Geography1 (Obj) 10.30 am - 11.30 am Biology 3 (Alternative to Practical Work) 1.00pm - 3.00pm

=============================

TUESDAY 15TH SEPT 2015 Physics 2 (Essay) 8.30am - 10.00am Physics 1 (Obj) 10.00am - 11.15am Geography 3 (Practical & Physical) 1.00 pm - 2.50 pm

=========================

WEDNESDAY 16TH SEPT 2015 Chemistry 3 (Alternative to Practical Work) & Essay) 8.30 am - 10.00 am Animal Husbandry (Alt A) 2 (Essay) 1.00 pm - 3.00 pm Animal Husbandry (Alt A) 1 (Obj) 3.00 pm - 4.00 pm

=============================
THURSDAY 17TH SEPT 2015 Literature-In-Eng 2(Prose) 8.30 am - 9.45 am Literature-In-Eng 1(Obj) 9.45 am - 10.45am Literature-In-Eng 3(Drama & Poetry) 1.00pm - 3.30 pm
=============================
FRIDAY 18TH SEPT 2015 Chemistry 2 (Essay) 8.30 am - 10.30am Chemistry 1 (Obj) 10.30 am - 11.30 am Government (Essay) 1.00pm - 3.00 pm Government (Obj) 3.00pm - 4.00 pm
=============================
SATURDAY 19TH SEPT 2015 English Language 2(Essay) 8.30 am -10.30 am English Language 1(Obj) 10.30 am - 11.30am
=============================

TUESDAY 22ND SEPT 2015 Agriculture 3 (Alt to Practical Work) * 8.30 am - 10.30 am

=============================

THURSDAY 24TH SEPT 2015 Christian Religious Studies(Essay) 8.30am - 10.30 am Christian Religious Studies(Obj) 10.30am -11.30 am Islamic Studies 2 (Essay) 8.30 am - 10.30am Islamic Studies 1 (Obj) 10.30 am - 11.20 am

=============================

FRIDAY 25TH SEPT 2015 Further Maths 2 (Essay) 8.30am - 11.10am Furthe Maths 1 (Obj) 2.00pm - 3.30pm

=============================

WEDNESDAY 30TH SEPT 2015 COMMERCE2(ESSAY) 2.OOpm-4.00pm COMMERCE 1(OBJ) 4.00pm-4.50pm

=============================

FRIDAY 2ND OCTOBER 2015 Animal Husbandry (Alt A) 3(Alt-Prac Work 8.30am-10.30am Agriculture.Science(Essay) 1.00pm-3.00pm Agriculture.Science(Obj) 3.00pm-4.00pm

=============================

Ensure You Subscribe With Us To Be Geting Your Answers Early.
Completed Timetable For 2015/2016 November/December Waec Gce